The major product of the reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction is a Friedel-Crafts alkylation of benzene with neopentyl chloride $(CH_3-C(CH_3)_2-CH_2-Cl)$ in the presence of a Lewis acid catalyst

Vedclass · Accepted Answer

$1,1-$dimethyl$-2-$phenylethane

Vedclass · Answer

(C) The reaction is a Friedel-Crafts alkylation of benzene with neopentyl chloride $(CH_3-C(CH_3)_2-CH_2-Cl)$ in the presence of a Lewis acid catalyst $(AlCl_3)$.$1$. The initial carbocation formed is the primary neopentyl carbocation $(CH_3-C(CH_3)_2-CH_2^+)$.$2$. Primary carbocations are unstable and undergo a $1,2-$methyl shift to form a more stable tertiary carbocation $(CH_3-C^+(CH_3)-CH_2-CH_3)$.$3$. This stable tertiary carbocation then undergoes electrophilic aromatic substitution with benzene to form the major product,which is $2-$methyl$-2-$phenylbutane (also known as tert-pentylbenzene or $1,1-$dimethyl$-2-$phenylethane structure).$4$. Looking at the options,the structure corresponding to the rearranged product is $1,1-$dimethyl$-2-$phenylethane (or $2-$methyl$-2-$phenylbutane).

Similar Questions

Meta-directing groups among the following are: $(a) -CN$,$(b) -COR$,$(c) -NHCOR$,$(d) -SO_3H$,$(e) -OCH_3$

Benzene can be obtained in the reaction:

Which of the following reactions takes place when a mixture of concentrated $HNO_3$ and $H_2SO_4$ reacts with benzene at $350 \ K$?

Which of the following reacts with benzene in the presence of anhydrous aluminum chloride to form acetophenone?

Which active species is involved in the nitration of benzene with concentrated nitric acid and concentrated sulfuric acid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module